In the previous short topic, I mentioned that “calculus” actually includes two ideas: differentiation and integration. I also introduced the mathematical definition of differentiation and what it represents. For more detail, see “A Gentle Introduction to Differentiation.”

The central idea of differentiation is not especially complicated: wherever a function is differentiable, we find the slope of the tangent line to its graph at that point. Different functions simply require different differentiation rules and formulas.

The previous topic approached differentiation through its mathematical definition. For integration, however, I want to begin with what it actually does and work backward toward the mathematical definition.

Understanding Integration by Counting Small Cells

Integration is commonly introduced through the problem of finding area.

When we want to estimate the area of an arbitrary shape, one basic method is to divide it into square cells and count them. As the diagrams show, using more and smaller cells lets the estimate approach the original area more closely. This is the basic intuition behind integration.

In a certain sense, integration is a way of calculating area.

An irregular shape overlaid with large grid cells for area estimation.
An irregular shape overlaid with large grid cells for area estimation.
The same shape overlaid with more, smaller grid cells for a finer area estimate.
The same shape overlaid with more, smaller grid cells for a finer area estimate.

If we estimate area with a grid, dividing the region into more cells generally gives a more effective estimate.

Defining the Definite Integral with Rectangle Sums and Limits

Now consider a function f(x). The area under its graph on the interval [a,b] can be estimated with rectangles. Suppose we divide [a,b] into n equal parts and label the x-coordinates of the division points x1, x2, x3 … xn+1.

Rectangles approximate the region between the graph of f(x) and the x-axis.
Rectangles approximate the region between the graph of f(x) and the x-axis.

The sum of the areas of these n rectangles can be written as follows:

Rectangle sum Sₙ = Σᵢ₌₁ⁿ f(xᵢ)Δx, where Δx = (b−a)/n.
Rectangle sum Sₙ = Σᵢ₌₁ⁿ f(xᵢ)Δx, where Δx = (b−a)/n.

As the number of rectangles increases, the expression can approximate the area under the function more closely.

Using the idea of a limit introduced in the differentiation article, we add a limit to this sum. This gives the mathematical definition of the definite integral:

Definite integral A = limₙ→∞ Sₙ = ∫ₐᵇ f(x)dx.
Definite integral A = limₙ→∞ Sₙ = ∫ₐᵇ f(x)dx.

Signed Area

One detail is especially important. Although both ideas involve area, the mathematical definition assigns negative values to regions where the function lies below the x-axis and positive values to regions where it lies above the x-axis.

Accumulation in Physics

That may still feel only half clear, but the short version is this: in the definite-integral setting discussed here, integration calculates signed area between a function and the x-axis. In the language of physics, it represents the accumulation of y=f(x) with respect to x.

Different functions cannot be integrated from the limit definition every time, so calculus provides different integration methods and formulas.

In high-school physics, we usually do not need to calculate areas bounded by highly complicated functions. Many common graph problems can still be handled with triangles or trapezoids.

Conclusion

Put simply, if you can use the triangle and trapezoid area formulas you learned earlier, you can already solve many familiar high-school physics graph problems XD. Treat this article as an introduction to a new mathematical tool and a new way of thinking.

References

Ch. 3 Key Concepts - Calculus Volume 1, URL: https://openstax.org/books/calculus-volume-1/pages/3-key-concepts

The Definite Integral, URL: https://math.libretexts.org/Courses/City_College_of_San_Francisco/CCSF_Calculus/05%3A_Investigating_Integrals/5.03%3A_The_Definite_Integral